2x^2-34x+2=0

Solution for 2x^2-34x+2=0 equation:

2x^2-34x+2=0

a = 2; b = -34; c = +2;
Δ = b2-4ac
Δ = -342-4·2·2
Δ = 1140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1140}=\sqrt{4*285}=\sqrt{4}*\sqrt{285}=2\sqrt{285}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-2\sqrt{285}}{2*2}=\frac{34-2\sqrt{285}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+2\sqrt{285}}{2*2}=\frac{34+2\sqrt{285}}{4}
$